Question

solve $4m + 7 \geq 19$ or $-m + 5 \leq 0$. then graph the solution set.
part a
select the solution set for $4m + 7 \geq 19$ or $-m + 5 \leq 0$.
a. $\\{m|m \geq 3\\}$
b. $\\{m|3 \leq m \leq 5\\}$
c. $\\{m|m \leq 3 \text{ or } m \geq 5\\}$
d. $\\{m|m \geq 5\\}$

Explanation:

Step1: Solve $4m + 7 \geq 19$

Subtract 7 from both sides:
$4m \geq 19 - 7$
$4m \geq 12$
Divide by 4:
$m \geq 3$

Step2: Solve $-m + 5 \leq 0$

Subtract 5 from both sides:
$-m \leq -5$
Multiply by -1 (reverse inequality):
$m \geq 5$

Step3: Combine "or" solution sets

The union of $m \geq 3$ and $m \geq 5$ is $m \geq 3$, since all values satisfying $m \geq 5$ already satisfy $m \geq 3$.

Answer:

A. $\{m|m \geq 3\}$