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solve for the indicated variable. fx + gy = h; for y (g ≠ 0) y = \\squa…

Question

solve for the indicated variable.
fx + gy = h; for y (g ≠ 0)
y = \square, g ≠ 0
(simplify your answer.)

Explanation:

Step1: Isolate the term with y

Subtract \( Fx \) from both sides of the equation \( Fx + Gy = H \).
\( Gy = H - Fx \)

Step2: Solve for y

Divide both sides of the equation by \( G \) (since \( G
eq0 \), division by \( G \) is valid).
\( y=\frac{H - Fx}{G} \)

Answer:

\( \frac{H - Fx}{G} \)