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Question
- solve the inequality 5x + 3 ≤ 12
Step1: Subtract 3 from both sides
$5x + 3 - 3 \leq 12 - 3$
$5x \leq 9$
Step2: Divide by 5 on both sides
$\frac{5x}{5} \leq \frac{9}{5}$
$x \leq \frac{9}{5}$
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$x \leq \frac{9}{5}$ (or $x \leq 1.8$)