QUESTION IMAGE
Question
solve for x knowing that the sum of the remote - interior angles should equal the exterior angle. (19x - 18)° (7x + 1)° (10x - 9)° o x = 5 o x = 4 o x = 9 o x = 16
Step1: Recall exterior - angle theorem
The exterior - angle of a triangle is equal to the sum of the two non - adjacent interior angles. So, $(19x - 18)=(7x + 1)+(10x - 9)$.
Step2: Simplify the right - hand side
$(7x + 1)+(10x - 9)=7x+1 + 10x-9=17x - 8$.
So the equation becomes $19x-18 = 17x - 8$.
Step3: Isolate the variable terms
Subtract $17x$ from both sides: $19x-17x-18=17x-17x - 8$, which simplifies to $2x-18=-8$.
Step4: Isolate the variable
Add 18 to both sides: $2x-18 + 18=-8 + 18$, so $2x = 10$.
Step5: Solve for x
Divide both sides by 2: $\frac{2x}{2}=\frac{10}{2}$, so $x = 5$.
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$x = 5$