QUESTION IMAGE
Question
- solve the logarithmic equation: $log_{2}(x) + log_{2}(x - 2) = 3$.
a. $x = 4$
b. $x = 3$
c. $x = 4, x = -2$
d. $x = 5$
- if an investment grows continuously according to the formula $a = pe^{rt}$, and you want to double your money with a rate $r = 0.05$, which equation solves for the time $t$
a. $t = 0,05\ln(2)$
b. $2 = 1.05^{t}$
c. $2 = e^{0.05t}$
d. $1 = e^{0.05t}$
- convert $150^{\circ}$ to radians.
a. $\frac{2\pi}{3}$
b. $\frac{5\pi}{6}$
Response
Question 9
Step1: Combine log terms
$\log_2(x(x-2)) = 3$
Step2: Convert to exponential form
$x(x-2) = 2^3 = 8$
Step3: Expand and rearrange to quadratic
$x^2 - 2x - 8 = 0$
Step4: Factor quadratic
$(x-4)(x+2) = 0$
Step5: Check domain (x>2)
Reject $x=-2$ since $\log_2(-2)$ is undefined.
Step1: Set $A=2P$ (double the money)
$2P = Pe^{rt}$
Step2: Divide both sides by $P$
$2 = e^{rt}$
Step3: Substitute $r=0.05$
$2 = e^{0.05t}$
Step1: Use degree to radian formula
$\text{Radians} = \text{Degrees} \times \frac{\pi}{180}$
Step2: Substitute 150 degrees
$150 \times \frac{\pi}{180} = \frac{5\pi}{6}$
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A. $x = 4$
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