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QUESTION IMAGE

solve for the missing value. water (cups) ←┼───┼───┼───┼───┼───┼→ 0 2 4…

Question

solve for the missing value.
water (cups) ←┼───┼───┼───┼───┼───┼→
0 2 4 8 12
lemon juice (oz) ←┼───┼───┼───┼───┼───┼→
0 1.5 3 6

Explanation:

Step1: Find the ratio of lemon juice to water

First, we take the known values. When water is 2 cups, lemon juice is 1.5 oz. So the ratio of lemon juice to water is $\frac{1.5}{2} = 0.75$ oz per cup of water.

Step2: Determine the missing water value

We know that when lemon juice is 6 oz, let the water be $x$ cups. Using the ratio, we have $\frac{6}{x}=0.75$. Solving for $x$, we get $x = \frac{6}{0.75}=8$? Wait, no, wait. Wait, the water line has marks at 0,2,4, then a missing one, then 8, then another, then 12. The lemon juice has 0,1.5,3, then a missing one, then 6. Wait, maybe the missing water is between 4 and 8. Let's check the pattern. From 0 to 2 (water) is +2, lemon juice 0 to 1.5 is +1.5. From 2 to 4 (water +2), lemon juice 1.5 to 3 (+1.5). So the next water after 4 should be 4 + 2 = 6? Wait, no, wait the water line: 0,2,4, then?, 8, then?, 12. So the intervals between water marks: from 0 to 2 is 2, 2 to 4 is 2, so the next after 4 should be 6 (4+2), then 8 (6+2), then 10 (8+2), then 12 (10+2). Wait, but the lemon juice: 0,1.5,3, then?, 6. So lemon juice intervals: 0 to 1.5 is 1.5, 1.5 to 3 is 1.5, so next lemon juice after 3 should be 4.5, then 6. So when lemon juice is 6, water is 8? But the water line at 8 is marked. Wait, maybe the missing water is the one that corresponds to lemon juice 4.5? Wait, no, the problem is to solve for the missing value. Wait, maybe the missing water is the one where lemon juice is 4.5? Wait, no, let's re - examine.

Wait, the water (cups) axis: 0,2,4, [missing], 8, [missing], 12. The lemon juice (oz) axis: 0,1.5,3, [missing], 6. So the relationship between water (w) and lemon juice (l) seems linear. Let's find the equation of the line. When w = 0, l = 0. When w = 2, l = 1.5. So the slope $m=\frac{1.5 - 0}{2 - 0}=0.75$ oz per cup. So the equation is $l = 0.75w$.

Now, let's find the missing water when l is 6: $6 = 0.75w\Rightarrow w = 8$ (but 8 is already marked). Wait, maybe the missing water is between 4 and 8. Wait, when w = 4, l = 0.754 = 3 (which matches). Then the next w after 4: let's see the lemon juice after 3 is, say, when w = 6, l = 0.756 = 4.5. Then when w = 8, l = 6 (matches). So the missing water between 4 and 8 is 6. Wait, the water line has 0,2,4, then (let's call it $w_1$), then 8, then $w_2$, then 12. The lemon juice has 0,1.5,3, then $l_1$, then 6. So from w = 4, l = 3. Then the next w is 4 + 2 = 6 (since the water intervals are 2), and l = 0.756 = 4.5. Then w = 8, l = 6. So the missing water value (the one that is not marked yet, between 4 and 8) is 6. Wait, but the problem says "Solve for the missing value". Maybe the missing water is the one that corresponds to lemon juice 6? No, lemon juice 6 corresponds to water 8, which is marked. Wait, maybe the missing water is the one between 8 and 12? Wait, 8 + 2 = 10. Let's check l for w = 10: l = 0.7510 = 7.5. But the lemon juice axis only goes up to 6. Wait, maybe I misread the diagram. Wait, the water line: 0,2,4, then a tick, then 8, then a tick, then 12. The lemon juice line: 0,1.5,3, then a tick, then 6. So the ticks on water and lemon juice are aligned. So 0 (water) - 0 (lemon), 2 - 1.5, 4 - 3, then next water - next lemon, then 8 - 6. So the next water after 4 should be 6 (since 4 + 2 = 6), and next lemon after 3 should be 4.5 (3 + 1.5 = 4.5). Then 8 - 6 (8 is 6 + 2, 6 is 4.5 + 1.5). So the missing water value (the one between 4 and 8) is 6. Wait, but let's confirm with the ratio. From 0 to 2 (water) is 2 cups, lemon 0 to 1.5 (1.5 oz). So per 2 cups of water, 1.5 oz of lemon juice. So the water marks are at 0,2,4,6…

Answer:

The missing water value is 6 cups.