Question

solve for x to the nearest tenth.

Explanation:

Step1: Find vertical and horizontal differences

The vertical difference is $8 - 4=4$, and the horizontal difference is 10.

Step2: Apply Pythagorean theorem

By the Pythagorean theorem $a^{2}+b^{2}=c^{2}$, where $a = 4$, $b = 10$, and $c=x$. So $x=\sqrt{4^{2}+10^{2}}=\sqrt{16 + 100}=\sqrt{116}$.

Step3: Calculate the value of $x$

$\sqrt{116}\approx10.8$.

Answer:

$10.8$