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Question
solve for the other leg and for the hypotenuse of the 45 - 45 - 90 triangle. a. u = 7 and v = 7 b. u = 7 and v = 7\sqrt{2} c. u = 7\sqrt{2} and v = 7 d. u = 7\sqrt{2} and v = 7\sqrt{2}
Step1: Recall 45 - 45 - 90 triangle property
In a 45 - 45 - 90 triangle, the two legs are of equal length. Given one leg is 7, so the other leg \(v = 7\).
Step2: Use Pythagorean theorem for hypotenuse
For a right - triangle \(a^{2}+b^{2}=c^{2}\). In a 45 - 45 - 90 triangle with legs \(a = b=7\), then \(c=\sqrt{7^{2}+7^{2}}=\sqrt{49 + 49}=\sqrt{98}=7\sqrt{2}\), so \(u = 7\sqrt{2}\).
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C. \(u = 7\sqrt{2}\) and \(v = 7\)