Question

solve the problem.
w = 0.62g² - 0.03g + 10.6 models the average weight in ounces for a mouse who is fed g grams of a special food per day. use the model to find and interpret the result when g = 15.
a when g = 15, p = 149.65; when a mouse is fed 15 grams of the special food per day, its average weight is 149.65 ounces.
b when g = 15, p = 19.45; the average amount of the special food that 15 mice should be fed is 19.45 ounces.
c when g = 15, p = 150.07; 15 mice gained an average of 150.07 ounces per day when fed the special food.
d when g = 15, p = 298.05; when a mouse is fed an average of 298.05 ounces of the special food per day, its weight will be at least 15 ounces.

Explanation:

Step1: Substitute g = 15 into the formula

Substitute \(g = 15\) into \(W=0.62g^{2}-0.03g + 10.6\). First calculate \(g^{2}=15^{2}=225\).

Step2: Calculate each term

Calculate \(0.62\times225 = 139.5\), \(0.03\times15=0.45\).

Step3: Find the value of W

\(W=139.5- 0.45+10.6=149.65\). The formula gives the average weight of a mouse in ounces when fed \(g\) grams of special - food per day. So when \(g = 15\), the average weight of a mouse is 149.65 ounces.

Answer:

A. When \(g = 15\), \(W = 149.65\); When a mouse is fed 15 grams of the special food per day, its average weight is 149.65 ounces.