Question

solve the problem.

an electric company has the following rate schedule for electricity usage in single - family residences:

monthly service charge $4.93

per kilowatt service charge
1st 300 kilowatts $0.11589/kw
over 300 kilowatts $0.13321/kw

what is the charge for using 300 kilowatts in one month?
what is the charge for using 375 kilowatts in one month?
construct a function that gives the monthly charge c for x kilowatts of electricity.

Explanation:

Answer:

For using 300 kilowatts: \( 4.93 + 300\times0.11589 = 4.93 + 34.767 = 39.697 \approx 39.70 \) dollars
For using 375 kilowatts: \( 4.93 + 300\times0.11589 + (375 - 300)\times0.13321 = 4.93 + 34.767 + 75\times0.13321 = 39.697 + 9.99075 = 49.68775 \approx 49.69 \) dollars
Function: \( C(x)=

$$\begin{cases}4.93 + 0.11589x, & 0\leq x\leq300\\4.93 + 300\times0.11589 + 0.13321(x - 300), & x > 300\end{cases}$$

\) (or simplified: \( C(x)=

$$\begin{cases}4.93 + 0.11589x, & 0\leq x\leq300\\0.13321x - 4.986, & x > 300\end{cases}$$

\))