Question

solve for x. round to the nearest tenth of a degree, if necessary. answer attempt 1 out of 2 x =

Explanation:

Step1: Identify trigonometric ratio

In right triangle \( PQR \) (right - angled at \( Q \)), we know the lengths of the opposite side (\( QR \)) and the hypotenuse (\( PR \)) with respect to angle \( x \). Wait, no, \( PQ = 5.7 \), \( PR=7 \), and \( \angle Q = 90^{\circ} \). So, \( \cos(x)=\frac{\text{adjacent}}{\text{hypotenuse}}=\frac{PQ}{PR} \)
\( \cos(x)=\frac{5.7}{7} \)

Step2: Solve for \( x \)

First, calculate \( \frac{5.7}{7}\approx0.8143 \)
Then, \( x = \arccos(0.8143) \)
Using a calculator, \( x\approx35.4^{\circ} \) (rounded to the nearest tenth of a degree)

Answer:

\( x\approx35.4^{\circ} \)