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solve for x. round to the nearest tenth if necessary. right triangle wi…

Question

solve for x. round to the nearest tenth if necessary.
right triangle with legs 25 and x, hypotenuse 65
options:
x=35
x=45
x=60
x=65
x=70

Explanation:

Step1: Identify the triangle type

This is a right triangle, so we use the Pythagorean theorem: \(a^2 + b^2 = c^2\), where \(c\) is the hypotenuse, and \(a\), \(b\) are the legs. Here, \(a = 25\), \(c = 65\), and \(b = x\).

Step2: Rearrange the formula to solve for \(x\)

We get \(x^2 = c^2 - a^2\). Substitute the values: \(x^2 = 65^2 - 25^2\).

Step3: Calculate the squares

\(65^2 = 4225\) and \(25^2 = 625\). So \(x^2 = 4225 - 625 = 3600\).

Step4: Take the square root

\(x = \sqrt{3600} = 60\).

Answer:

\(x = 60\) (corresponding to the option "x = 60")