Question

solve for ( x ). round to the nearest tenth, if necessary.
right triangle pqo with right angle at p, pq = 33, po = ( x ), angle at o is ( 19^circ )
answer attempt 1 out of 2
( x = ) input box submit answer

Explanation:

Step1: Identify trigonometric ratio

We use tangent: $\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}$
Here, $\theta=19^\circ$, opposite side $=33$, adjacent side $=x$.
So $\tan(19^\circ) = \frac{33}{x}$

Step2: Rearrange to solve for x

Rearrange the formula to isolate $x$:
$x = \frac{33}{\tan(19^\circ)}$

Step3: Calculate the value

First, find $\tan(19^\circ) \approx 0.3443$
Then $x \approx \frac{33}{0.3443} \approx 95.8$

Answer:

$x = 95.8$