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solve for x. round to the nearest tenth, if necessary. triangle tuv wit…

Question

solve for x. round to the nearest tenth, if necessary. triangle tuv with right angle at u, angle at t is 40 degrees, side tu is 64, side tv is x

Explanation:

Step1: Identify trigonometric ratio

We use cosine: $\cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}}$
Here, $\theta=40^\circ$, adjacent side $=64$, hypotenuse $=x$.

Step2: Rearrange to solve for $x$

$x = \frac{64}{\cos(40^\circ)}$

Step3: Calculate value

First, $\cos(40^\circ) \approx 0.7660$, so $x \approx \frac{64}{0.7660} \approx 83.55$

Step4: Round to nearest tenth

$x \approx 83.6$

Answer:

$83.6$