Question

solve $0 = 4x^{2}+12x + 9$. select the equation that shows the correct substitution of $a$, $b$, and $c$ in the quadratic formula. $\boldsymbol{x = \frac{12 \pm \sqrt{12^{2}-4(4)(9)}}{2(4)}}$ $\boldsymbol{x = \frac{-12 \pm \sqrt{12^{2}+4(4)(9)}}{2(4)}}$ $\boldsymbol{x = \frac{-12 \pm \sqrt{12^{2}-4(4)(9)}}{2(4)}}$

Explanation:

Step1: Identify a, b, c

For $ax^2+bx+c=0$, here $a=4$, $b=12$, $c=9$.

Step2: Recall quadratic formula

The formula is $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$.

Step3: Substitute values into formula

Substitute $a=4$, $b=12$, $c=9$:
$x=\frac{-12\pm\sqrt{12^2-4(4)(9)}}{2(4)}$

Answer:

$\boldsymbol{x = \dfrac{-12 \pm \sqrt{12^{2} - 4(4)(9)}}{2(4)}}$