Question

solve the system of equations \\(\

$$\begin{cases} -3x + y = 12 \\\\ 6x - 2y = 18 \\end{cases}$$

\\)

Explanation:

Step1: Simplify the second equation

Divide the second equation \(6x - 2y = 18\) by 2, we get \(3x - y = 9\).

Step2: Add the two equations

Now we have the first equation \(-3x + y = 12\) and the simplified second equation \(3x - y = 9\). Add them together: \((-3x + y)+(3x - y)=12 + 9\). Simplifying the left side: \(-3x + y+3x - y = 0\), and the right side is \(21\). So we get \(0 = 21\), which is a contradiction.

Answer:

The system of equations has no solution.