QUESTION IMAGE
Question
solve the system of equations by graphing
\
$$\begin{cases}
x = -3 \\\\
y = \\frac{4}{3}x + 2
\\end{cases}$$
options: (-3, -7), (-3, 2), (-3, -6), (-3, 6)
Step1: Substitute \( x = -3 \) into the second equation
We have the system \(
$$\begin{cases}x = -3\\y=\frac{4}{3}x + 2\end{cases}$$
\). Substitute \( x=-3 \) into \( y=\frac{4}{3}x + 2 \).
\( y=\frac{4}{3}\times(-3)+2 \)
Step2: Calculate the value of \( y \)
First, calculate \(\frac{4}{3}\times(-3)\), which is \( -4 \). Then add 2: \( y=-4 + 2=-2 \).
Step3: Determine the solution
Since \( x = -3 \) and \( y=-2 \), the solution to the system is the ordered pair \((-3,-2)\).
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\((-3, -2)\)