Question

solve the system of equations.
$13x - 6y = 22$
$x = y + 6$
$x = square$
$y = square$
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Explanation:

Step1: Substitute $x=y+6$ into first equation

$13(y+6) - 6y = 22$

Step2: Expand and simplify left side

$13y + 78 - 6y = 22$
$7y + 78 = 22$

Step3: Isolate term with $y$

$7y = 22 - 78$
$7y = -56$

Step4: Solve for $y$

$y = \frac{-56}{7} = -8$

Step5: Substitute $y=-8$ into $x=y+6$

$x = -8 + 6 = -2$

Answer:

$x = -2$
$y = -8$