Question

1 solve the system of equations by substitution:
$y = -2x - 1$
$3x - 4y = -40$

Explanation:

Step1: Substitute $y$ into second equation

Substitute $y=-2x-1$ into $3x-4y=-40$:
$3x - 4(-2x - 1) = -40$

Step2: Simplify and solve for $x$

Expand and combine like terms:
$3x + 8x + 4 = -40$
$11x + 4 = -40$
$11x = -44$
$x = \frac{-44}{11} = -4$

Step3: Substitute $x$ to find $y$

Plug $x=-4$ into $y=-2x-1$:
$y = -2(-4) - 1 = 8 - 1 = 7$

Answer:

$x=-4$, $y=7$ (or the ordered pair $(-4, 7)$)