Question

solve the system of linear equations by substitution.\\( x = 16 - 4y \\)\\( 3x + 4y = 8 \\)

Explanation:

Step1: Substitute $x$ into 2nd equation

$3(16-4y)+4y=8$

Step2: Simplify to solve for $y$

$48-12y+4y=8 \implies 48-8y=8 \implies -8y=8-48 \implies -8y=-40 \implies y=5$

Step3: Substitute $y=5$ into 1st equation

$x=16-4(5)=16-20=-4$

Answer:

$(-4, 5)$