Question

solve for the variable
1 ( x + 6 = 14 )
2 ( y - 9 = 3 )
3 ( 4a = 20 )
4 ( \frac{b}{5} = 6 )
5 ( m + 11 = 25 )

Explanation:

Step1: Solve \( x + 9 = 14 \)

Subtract 9 from both sides: \( x = 14 - 9 \)
\( x = 5 \)

Step2: Solve \( y - 6 = 3 \)

Add 6 to both sides: \( y = 3 + 6 \)
\( y = 9 \)

Step3: Solve \( 4a = 20 \)

Divide both sides by 4: \( a = \frac{20}{4} \)
\( a = 5 \)

Step4: Solve \( b \div 5 = 6 \)

Multiply both sides by 5: \( b = 6 \times 5 \)
\( b = 30 \)

Step5: Solve \( m + 11 = 25 \)

Subtract 11 from both sides: \( m = 25 - 11 \)
\( m = 14 \)

Answer:

\( x = 5 \)
\( y = 9 \)
\( a = 5 \)
\( b = 30 \)
\( m = 14 \)