Question

solve for v. you can choose to show your work below or solve on paper, your answer on zearn. \\(\frac{2}{3}v + 9 = v + 15\\) \\(v = \square\\)

Explanation:

Step1: Subtract $\frac{2}{3}v$ from both sides

To isolate the variable terms, we subtract $\frac{2}{3}v$ from each side of the equation $\frac{2}{3}v + 9 = v + 15$. This gives us $9 = v - \frac{2}{3}v + 15$. Simplifying the right - hand side, $v-\frac{2}{3}v=\frac{1}{3}v$, so the equation becomes $9=\frac{1}{3}v + 15$.

Step2: Subtract 15 from both sides

To get the term with $v$ alone, we subtract 15 from both sides of the equation $9=\frac{1}{3}v + 15$. So, $9 - 15=\frac{1}{3}v$. Calculating the left - hand side, $9-15=-6$, and the equation is $-6=\frac{1}{3}v$.

Step3: Multiply both sides by 3

To solve for $v$, we multiply both sides of the equation $-6=\frac{1}{3}v$ by 3. Using the property of equality, $3\times(-6)=3\times\frac{1}{3}v$. This simplifies to $v=-18$.

Answer:

$v = - 18$