Question

solving algebraic equations

1. (5x - 2 = -9 + 2x)
2. (-8 = -(y + 6))
3. (-(7 - 4m) = 9)
4. (x - 1 = 5x + 3x - 8)
5. (2(4x - 3) - 8 = 4 + 2x)
6. (4y + 5 = -31y + 10y)

Explanation:

Let's solve one of the equations, say problem 26: \(5x - 2=-9 + 2x\)

Step1: Subtract \(2x\) from both sides

To get all \(x\) terms on one side, we subtract \(2x\) from both sides.
\(5x-2x - 2=-9 + 2x-2x\)
Simplifying, we have \(3x - 2=-9\)

Step2: Add 2 to both sides

To isolate the term with \(x\), we add 2 to both sides.
\(3x - 2 + 2=-9 + 2\)
Simplifying, we get \(3x=-7\)

Step3: Divide by 3

To solve for \(x\), we divide both sides by 3.
\(x =-\frac{7}{3}\)

Answer:

\(x =-\frac{7}{3}\)

If you want solutions to other problems, please provide the clear problem statement (like the exact equation) and I will solve them similarly.