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Question
3.4: solving for sides
degree mode!!! - \mode\ → highlight \degree\
steps to find a missing side
- identify the \opposite\, \adjacent\, and \hypotenuse\ sides of your right triangle, based off of the given angle!
- choose the correct trig function based off of the two given sides (cosine, sine, or tangent!)
- set up an equation.
- solve for x!
1.
2.
3.
4.
Step1: Recall tangent formula
For a right - triangle, $\tan\theta=\frac{\text{opposite}}{\text{adjacent}}$.
Step2: Solve for problem 1
In the first right - triangle, $\theta = 32^{\circ}$, the adjacent side to the angle is $17$ and the opposite side is $x$. Using the tangent formula $\tan\theta=\frac{\text{opposite}}{\text{adjacent}}$, we have $\tan32^{\circ}=\frac{x}{17}$. Then $x = 17\times\tan32^{\circ}$. Since $\tan32^{\circ}\approx0.6249$, $x\approx17\times0.6249 = 10.6233$.
Step3: Solve for problem 2
In the second right - triangle, $\theta = 29^{\circ}$, the adjacent side to the angle is $31$ and the opposite side is $x$. Using the tangent formula $\tan\theta=\frac{\text{opposite}}{\text{adjacent}}$, we have $\tan29^{\circ}=\frac{x}{31}$. Then $x = 31\times\tan29^{\circ}$. Since $\tan29^{\circ}\approx0.5543$, $x\approx31\times0.5543=17.1833$.
Step4: Solve for problem 3
In the third right - triangle, $\theta = 47^{\circ}$, the hypotenuse is $52$ and we want to find the side opposite the angle $x$. First, we know that $\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}$. So $\sin47^{\circ}=\frac{x}{52}$, and $x = 52\times\sin47^{\circ}$. Since $\sin47^{\circ}\approx0.7314$, $x\approx52\times0.7314 = 38.0328$.
Step5: Solve for problem 4
In the fourth right - triangle, $\theta = 72^{\circ}$, the adjacent side to the angle is $19$ and the opposite side is $x$. Using the tangent formula $\tan\theta=\frac{\text{opposite}}{\text{adjacent}}$, we have $\tan72^{\circ}=\frac{x}{19}$. Then $x = 19\times\tan72^{\circ}$. Since $\tan72^{\circ}\approx3.0777$, $x\approx19\times3.0777 = 58.4763$.
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- $x\approx10.62$
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