Question

a spinner has 4 equal - sized sections labeled a, b, c, and d. it is spun and a fair coin is tossed. what is the probability of spinning \c\ and flipping \heads\?
$\frac{1}{8}$
$\frac{1}{4}$
$\frac{1}{2}$
$\frac{3}{4}$

Explanation:

Step1: Find probability of spinning "C"

The spinner has 4 equal sections, so the probability of spinning "C" is $\frac{1}{4}$ (since there's 1 favorable outcome out of 4).

Step2: Find probability of flipping "heads"

A fair coin has 2 sides, so the probability of flipping "heads" is $\frac{1}{2}$ (1 favorable outcome out of 2).

Step3: Multiply the two probabilities

Since the two events (spinning the spinner and tossing the coin) are independent, we multiply their probabilities: $\frac{1}{4} \times \frac{1}{2} = \frac{1}{8}$.

Answer:

$\frac{1}{8}$ (corresponding to the option $\boldsymbol{\frac{1}{8}}$)