Question

1. spongebobs aunt and uncle, spongewilma and spongewilbur, have the biggest round eyes in the family. wilma is believed to be heterozygous for her round eye shape, while wilburs family brags that they are a pure line. complete the punnett square to show the possibilities that would result if spongewilma and spongewilbur had children.

(a) give the genotype for each person. wilma - ____ wilbur - ____
(b) complete the punnett square to show the possibilities that would result if they had children.
(c) what is the probability that the kids would have round eyes? ______ %
(d) what is the probability that the kids would be oval eyes? ______ %

Explanation:

Step1: Define genotypes

Let round eyes be dominant ($R$) and oval eyes be recessive ($r$).
Wilma (heterozygous): $Rr$
Wilbur (pure round): $RR$

Step2: Set up Punnett square

List gametes from each parent:
Wilma's gametes: $R, r$
Wilbur's gametes: $R, R$

Fill the Punnett square:

	$R$	$R$
$r$	$Rr$	$Rr$

Step3: Calculate round eye probability

Count genotypes with round eyes ($RR, Rr$): 4 out of 4 possible genotypes.
Probability: $\frac{4}{4} \times 100 = 100\%$

Step4: Calculate oval eye probability

Oval eyes require $rr$: 0 out of 4 possible genotypes.
Probability: $\frac{0}{4} \times 100 = 0\%$

Answer:

(a) Wilma - $Rr$, Wilbur - $RR$
(b) Completed Punnett square:

	$R$	$R$
$r$	$Rr$	$Rr$

(c) 100
(d) 0