Question

st. louis, missouri and washington, d.c. have very similar latitudes. (latitude measures how far north or south a place is, which in turn affects the temperature.) the box plots below show the daily high temperatures (in degrees celsius) that were recorded during july 2013 in each city. which pieces of information can be gathered from these box plots? choose all answers that apply:

Explanation:

To solve this, we analyze box - plot components (minimum, Q1, median, Q3, maximum, spread, skewness):

Step 1: Analyze Spread (Range/Interquartile Range)

• The range of a dataset in a box - plot is calculated as \( \text{Range}=\text{Maximum}-\text{Minimum} \), and the inter - quartile range (IQR) is \( \text{IQR} = Q_3 - Q_1 \).
• For St. Louis, the whiskers extend further out (especially on the left) compared to Washington, D.C. This means the range (and potentially IQR) of daily high temperatures in St. Louis is larger. So we can conclude that St. Louis had a greater spread of daily high temperatures.

Step 2: Analyze Median (Center)

• The median is represented by the line inside the box. By visually inspecting the box - plots, we can see that the median line for both cities seems to be around the same value (near 30°C). So the median daily high temperature is similar for both cities.

Step 3: Analyze Skewness

• A box - plot is skewed left if the left whisker is longer and the median is closer to the right of the box; it is skewed right if the right whisker is longer and the median is closer to the left of the box.
• St. Louis's box - plot has a longer left whisker, so its daily high temperatures are skewed left. Washington, D.C.'s box - plot is more symmetric (or less skewed) as the whiskers are more balanced around the box.

Since the problem is about analyzing box - plots (a statistical tool), the sub - field of Mathematics (Statistics) is the most appropriate.

If we assume the possible options (even though not fully listed here, based on box - plot analysis) are statements like:

• St. Louis had a greater spread of daily high temperatures.
• The median daily high temperature was similar for both cities.
• St. Louis's daily high temperatures were skewed left, while Washington, D.C.'s were more symmetric.

We would select all the options that match the above - derived conclusions.

For example, if the options were:
A. St. Louis had a greater spread of daily high temperatures.
B. The median daily high temperature was the same for both cities.
C. St. Louis's daily high temperatures were skewed left.

The answers would be A, B, C (depending on the exact visual match of the box - plots, but the above is the general analysis).

If we consider the process of analyzing box - plots:

Step 1: Analyze Spread

By comparing the length of whiskers and boxes, St. Louis has a wider spread (longer whiskers overall) than Washington, D.C.

Step 2: Analyze Median

The median line (inside the box) for both cities is at a similar position on the temperature axis, so the median is similar.

Step 3: Analyze Skewness

St. Louis's box - plot has a longer left whisker, indicating left - skewed data; Washington, D.C.'s plot has more balanced whiskers, indicating less skewness.

Answer:

(The specific options that apply, e.g., if options are as assumed above: A, B, C)