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to start cooking dinner, austin put two identical pots of water on a st…

Question

to start cooking dinner, austin put two identical pots of water on a stove to boil. the amount of water in each pot was the same, but one pot had a lid on it and the other one did not. this table shows how the temperature of each pot of water changed over 4 minutes. pot of water | initial temperature (°c) | final temperature (°c) pot of water with a lid | 24 | 83 pot of water without a lid | 22 | 59 the next time austin boils a pot of water, he wants it to warm up quickly. what should he do to maximize the rate of thermal energy transfer into the pot of water? put the lid on the pot leave the lid off the pot either; the rate of thermal energy transfer is the same whether or not the lid is on the pot

Explanation:

Brief Explanations

First, calculate the temperature change for each pot over 4 minutes. For the lidded pot: $83^\circ\text{C} - 24^\circ\text{C} = 59^\circ\text{C}$. For the uncovered pot: $59^\circ\text{C} - 22^\circ\text{C} = 37^\circ\text{C}$. A larger temperature change over the same time means a higher rate of thermal energy transfer into the water, as the lid reduces heat loss to the surroundings, allowing more thermal energy to stay in the water and increase its temperature faster.

Answer:

put the lid on the pot