Question

statements

1. $overline{ab}congoverline{fg}$
2. $overleftrightarrow{bf}$ bisects $overline{ac}$ and $overline{dg}$.
3. $overline{bc}congoverline{ab}$, $overline{fg}congoverline{df}$

4.

1. $overline{bc}congoverline{df}$

reasons

1. given
2. given
3. definition of segment bisector
4. transitive property of segment congruence

5.

Explanation:

Answer:

1. \( \overline{BC}\cong\overline{DF} \)
2. Transitive Property of Segment Congruence (since \( \overline{BC}\cong\overline{AB} \), \( \overline{AB}\cong\overline{FG} \), \( \overline{FG}\cong\overline{DF} \))