Question

stefano accidentally dropped his sunglasses off the edge of a canyon as he was looking down. the height, h(t), in meters (as it relates to sea level), of the sunglasses after t seconds, is shown in the table.

height of sunglasses over time

t	h(t)
1	5.1
2	-9.6
3	-34.1
4	-68.4
5	-112.5
6	-166.4
7	-230.1

during its descent, the pair of sunglasses passed by a climber in the canyon 6 seconds after stefano dropped them. to the nearest meter, what is the difference in elevation between stefano and the climber?
166 meters
240 meters
230 meters
176 meters

Explanation:

Step1: Determine Stefano's height

When $t = 0$, the height of the sunglasses $h(0)=10$ meters. So Stefano's height relative to sea - level is 10 meters.

Step2: Determine the climber's height

When $t = 6$, the height of the sunglasses $h(6)=- 166.4$ meters. So the climber's height relative to sea - level is approximately - 166 meters (rounded to the nearest meter).

Step3: Calculate the height difference

The difference in elevation $\Delta h=10-(-166)=10 + 166=176$ meters.

Answer:

176 meters