Question

step 2
canceling h from the numerator and denominator and evaluating the limit, we conclude the following
$f(x) = \lim_{h \to 0} \frac{\frac{1}{2}h}{h}$
$= \lim_{h \to 0} \frac{1}{\square}$
$= \square$
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Explanation:

Step1: Cancel common factor $h$

$f'(x) = \lim_{h \to 0} \frac{\frac{1}{2}h}{h} = \lim_{h \to 0} \frac{1}{2}$

Step2: Evaluate the limit

Since $\frac{1}{2}$ is constant, the limit equals the constant.

Answer:

$\frac{1}{2}$