Question

a stone with a mass of 100 kg sits on the ground. gravity acts on the stone at a rate of 9.8 m/s². what is the normal force acting on the stone, keeping it at rest? (1 point)

9.8 n

980 n

91.2 n

98 n

Explanation:

Step1: Identify relevant formula

The force due to gravity is $F = mg$, where $m$ is mass and $g$ is acceleration due to gravity. The normal force $N$ balances the force of gravity when the object is at rest on a horizontal surface.

Step2: Calculate force of gravity

Given $m = 100$ kg and $g=9.8$ m/s². Using $F = mg$, we have $F=100\times9.8 = 980$ N. Since the stone is at rest, the normal force $N$ equals the force of gravity. So $N = 980$ N.

Answer:

980 N