Question

a student’s motion is captured using a motion detector and displayed on the graph shown. use the graph to answer the following questions. right is defined as positive. answers have a 5% tolerance to allow for estimation. describe the direction of travel: left describe the motion: moving at constant speed what is the distance traveled? yellow box m what is the final speed? yellow box m/s

Explanation:

Distance Traveled

Step1: Identify initial and final positions

Initial position ($x_0$) is 35 m (from the graph, at t=0, position is 35 m), final position ($x_f$) is 0 m (at t=12 s, position is 0 m).

Step2: Calculate distance traveled

Distance is the absolute difference between initial and final positions. So, distance $d = |x_f - x_0| = |0 - 35| = 35$ m.

Step1: Recall speed formula for constant speed motion

Speed $v = \frac{\text{distance traveled}}{\text{time taken}}$.

Step2: Identify time taken

Time taken ($t$) is 12 s (from t=0 to t=12 s).

Step3: Calculate speed

Using distance (35 m) and time (12 s), $v = \frac{35}{12} \approx 2.92$ m/s (or with 5% tolerance, it can be calculated as $\frac{35}{12} \approx 2.92$, which is close to 2.9 or 3.0 depending on estimation, but precisely $\frac{35}{12} \approx 2.92$).

Answer:

35

Final Speed