Question

a student tests the second law of motion by accelerating a block of ice at a rate of 3.5 m/s2. if the ice has a mass of 12.5 kg, what force must the student apply to the ice? (a) what are you solving for? a force b acceleration c mass (b) what is the equation you need to use to solve this problem? a $a = \frac{f}{m}$ b $f = m\cdot a$ c $m = \frac{f}{a}$ (c) what is your answer? a 3.57 b 43.75

Explanation:

Step1: Identify what's asked

We need to find force.

Step2: Select the formula

Newton's second - law formula is $F = m\times a$.

Step3: Substitute values

Given $m = 12.5$ kg and $a=3.5$ m/s², so $F=12.5\times3.5$.

Step4: Calculate

$F = 43.75$ N.

Answer:

(a) A. force
(b) B. $F = m\times a$
(c) B. 43.75