Question

1. subtract the mixed numbers $9\frac{2}{5} - 7\frac{5}{10}$.\

\bigcirc $1\frac{9}{10}$\
\bigcirc $2\frac{1}{5}$\
\bigcirc $2\frac{3}{10}$\
\bigcirc $2\frac{1}{10}$

Explanation:

Step1: Convert to common denominator

Convert \(9\frac{2}{5}\) to tenths: \(9\frac{2}{5}=9\frac{4}{10}\)

Step2: Subtract the mixed numbers

Subtract the whole numbers and fractions: \(9\frac{4}{10}-7\frac{5}{10}=(8\frac{14}{10})-7\frac{5}{10}=1\frac{9}{10}\)? Wait, no, correction: \(9\frac{4}{10}-7\frac{5}{10}\), since \(4/10 < 5/10\), borrow 1 from 9: \(8\frac{14}{10}-7\frac{5}{10}=(8 - 7)+(\frac{14}{10}-\frac{5}{10})=1\frac{9}{10}\)? Wait, no, wait the options have \(1\frac{9}{10}\) as first option. Wait, let's recalculate:

\(9\frac{2}{5}=9+\frac{2}{5}=9+\frac{4}{10}\)

\(7\frac{5}{10}=7+\frac{5}{10}\)

Subtract: \(9\frac{4}{10}-7\frac{5}{10}=(9 - 7)+(\frac{4}{10}-\frac{5}{10})=2-\frac{1}{10}=1\frac{9}{10}\)

Yes, that's correct.

Answer:

\(1\frac{9}{10}\) (corresponding to the first option: \(1\frac{9}{10}\))