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Question
subtract the rational expressions to find the difference: \\(\frac{x^2 - 2}{4x - 7} - \frac{x + 4}{4x - 7}\\) (1 point) \\(\frac{-6}{4x - 7}\\) \\(\frac{x^2 - x - 6}{4x - 7}\\) \\(\frac{x^2 - x + 2}{4x - 7}\\) \\(\frac{x^2 - x - 6}{8x - 14}\\)
Step1: Subtract numerators (common denominator)
Since the denominators are the same ($4x - 7$), we subtract the numerators: $(x^2 - 2) - (x + 4)$.
$$(x^2 - 2) - (x + 4) = x^2 - 2 - x - 4$$
Step2: Simplify the numerator
Combine like terms: $x^2 - x + (-2 - 4) = x^2 - x - 6$.
Step3: Write the result over the common denominator
The denominator remains $4x - 7$, so the expression becomes $\frac{x^2 - x - 6}{4x - 7}$.
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$\frac{x^2 - x - 6}{4x - 7}$ (corresponding to the option with this expression)