Question

suppose that 19% of people have a dog, 20% of people have a cat, and 6% of people own both. what is the probability that someone owns a dog or a cat? the probability of a person having a dog or a cat is (type an integer or a decimal.)

Explanation:

Step1: Recall probability formula

Use the formula $P(A\cup B)=P(A)+P(B)-P(A\cap B)$. Let $A$ be the event of having a dog and $B$ be the event of having a cat. So $P(A) = 0.19$, $P(B)=0.20$ and $P(A\cap B)=0.06$.

Step2: Calculate the probability

Substitute the values into the formula: $P(A\cup B)=0.19 + 0.20- 0.06$.
$P(A\cup B)=0.33$

Answer:

$0.33$