Question

suppose that an object is thrown upward from ground level with an initial velocity of 96 ft/sec. its height after t seconds is a function h given by h(t)= - 16t² + 96t. a) find an equivalent expression for h(t) by factoring out a common factor with a negative coefficient. b) check your factoring by evaluating both expressions for h(t) at t = 2. a) the factored expression is - 16t(t - 6) (factor completely.) b) - 16(2)²+96(2)=128 - 16(2)(2 - 6)=□

Explanation:

Step1: Evaluate -16(2)(2 - 6)

First, calculate the value inside the parentheses: $2-6=-4$. Then multiply: $-16\times2\times(-4)=128$.

Step2: Evaluate -16(2)^2+96(2)

Calculate the exponent first: $(2)^2 = 4$. Then perform multiplications: $-16\times4=-64$ and $96\times2 = 192$. Then add: $-64 + 192=128$.

Answer:

128