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suppose that point p is on a circle with radius r, and ray op is rotati…

Question

suppose that point p is on a circle with radius r, and ray op is rotating with angular speed ω. complete parts (a) through (c). r = 6 cm, ω = $\frac{pi}{4}$ radian per sec, t = 4 sec (a) what is the angle generated by p in time t? θ = □ radian (simplify your answer. type an exact answer, using π as needed. use integers or fractions for any numbers in the expression.)

Explanation:

Step1: Recall the formula for angular - displacement

The formula for the angle $\theta$ generated in time $t$ with angular speed $\omega$ is $\theta=\omega t$.

Step2: Substitute the given values

Given $\omega = \frac{\pi}{4}$ radian per sec and $t = 4$ sec. Substitute these values into the formula: $\theta=\frac{\pi}{4}\times4$.

Step3: Simplify the expression

$\theta=\pi$ radians.

Answer:

$\pi$