Question

suppose set a contains 93 elements and set b contains 32 elements. if sets a and b have 28 elements in common, what is the total number of elements in either set a or set b.
answer = elements
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Explanation:

Step1: Recall union of sets formula

The formula for the number of elements in the union of two sets is $n(A \cup B) = n(A) + n(B) - n(A \cap B)$, where $n(A)$ is the number of elements in set A, $n(B)$ is the number of elements in set B, and $n(A \cap B)$ is the number of common elements.

Step2: Substitute given values

Substitute $n(A)=93$, $n(B)=32$, $n(A \cap B)=28$ into the formula:
$n(A \cup B) = 93 + 32 - 28$

Step3: Calculate the result

First add 93 and 32: $93+32=125$. Then subtract 28: $125-28=97$.

Answer:

97 elements