Question

a survey asked male and female students about whether they prefer gym or choir class. the table shows results of the survey.

		class
gender	male			50
	female	23
	total		49	106

what is the probability that a randomly selected male student prefers gym class?

• $\frac{16}{50}$
• $\frac{57}{106}$
• $\frac{34}{50}$
• $\frac{33}{56}$
• $\frac{23}{50}$

Explanation:

Step1: Find total female students

Total students = 106, total male = 50, so female total = \(106 - 50 = 56\).

Step2: Find male gym preference

Total gym = Total - Choir total = \(106 - 49 = 57\). Female gym = 23, so male gym = \(57 - 23 = 34\).

Step3: Calculate probability

Probability = \(\frac{\text{Male gym}}{\text{Total male}} = \frac{34}{50}\).

Answer:

\(\boldsymbol{\frac{34}{50}}\) (corresponding to the option with \(\frac{34}{50}\))