Question

svlc algebra 1a - standard (15260)
literal equations

in physics class, carrie learns that a force, f, is equal to the mass of an object, m, times its acceleration, a. she writes the equation f = ma.
using this formula, what is the acceleration of an object with f = 7.92 newtons and m = 3.6 kilograms? express your answer to the nearest tenth.
note: the unit for force (the newton) is measured in \\(\frac{kg\cdot m}{s^2}\\).

\\(1.8\\ \frac{m}{s^2}\\)\\(0.5\\ \frac{m}{s^2}\\)\\(4.9\\ \frac{m}{s^2}\\)\\(2.2\\ \frac{m}{s^2}\\)

quiz
mark and return10 of 10save & exit

Explanation:

Step1: Recall the formula

We know the formula is \( F = ma \), and we need to solve for \( a \). So we can rearrange the formula to \( a=\frac{F}{m} \).

Step2: Substitute the values

Given \( F = 7.92 \) newtons and \( m = 3.6 \) kilograms. Substitute these values into the formula \( a=\frac{F}{m} \), we get \( a=\frac{7.92}{3.6} \).

Step3: Calculate the result

Calculate \( \frac{7.92}{3.6}=2.2 \). So the acceleration \( a \) is \( 2.2\frac{m}{s^2} \).

Answer:

2.2 \(\frac{m}{s^2}\) (corresponding to the option: 2.2 \(\frac{m}{s^2}\))