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svlc algebra 1a - standard (15260) solving linear equations: variables …

Question

svlc algebra 1a - standard (15260)
solving linear equations:
variables on both sides
what is the solution to the linear equation?
$2.8y + 6 + 0.2y = 5y - 14$
$y = 10$
$y = -1$
$y = -10$
$y = 1$

Explanation:

Step1: Combine like terms on left

Combine \(2.8y\) and \(0.2y\): \(2.8y + 0.2y = 3y\), so equation becomes \(3y + 6 = 5y - 14\)

Step2: Subtract \(3y\) from both sides

\(3y - 3y + 6 = 5y - 3y - 14\), simplifies to \(6 = 2y - 14\)

Step3: Add 14 to both sides

\(6 + 14 = 2y - 14 + 14\), gives \(20 = 2y\)

Step4: Divide both sides by 2

\(\frac{20}{2} = \frac{2y}{2}\), results in \(y = 10\)

Answer:

\(y = 10\) (corresponding to the option: \(y = 10\))