Question

a system of equations is given.\

$$\begin{cases}y = -3x - 1\\\\y = 2x + 4\\end{cases}$$

\
show hints\
fill in the blanks to solve the system.\
-3x - 1 = \square\
-1 = \square\
\square = 5x\
\square = x\
y = -3(\square) - 1

Explanation:

Step1: Substitute y from second equation

$-3x - 1 = 2x + 4$

Step2: Move -3x to right side

$-1 = 5x + 4$

Step3: Move 4 to left side

$-5 = 5x$

Step4: Divide both sides by 5

$-1 = x$

Step5: Substitute x into first equation

$y = -3(-1) - 1$

Answer:

$-3x - 1 = \boldsymbol{2x + 4}$
$-1 = \boldsymbol{5x + 4}$
$\boldsymbol{-5} = 5x$
$\boldsymbol{-1} = x$
$y = -3(\boldsymbol{-1}) - 1$

The solution to the system is $x=-1$, $y=2$