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the table below shows the number of grams of carbohydrates, x, and the …

Question

the table below shows the number of grams of carbohydrates, x, and the number of calories, y, of six different foods.

carbohydrates (x)calories (y)
9.5138
10147
689
7108
462

which of the following is the linear equation that best matches the data?

○ ( y = 15x )

○ ( y = 0.07x )

○ ( y = 0.1x - 0.4 )

○ ( y = 14.1x + 5.8 )

Explanation:

Step1: Test the first option \( y = 15x \)

For \( x = 8 \), \( y = 15\times8 = 120 \) (matches). For \( x = 9.5 \), \( y = 15\times9.5 = 142.5 \), but the actual \( y \) is 138 (close but not exact). For \( x = 10 \), \( y = 15\times10 = 150 \), actual \( y = 147 \) (close). For \( x = 6 \), \( y = 15\times6 = 90 \), actual \( y = 89 \) (very close). For \( x = 7 \), \( y = 15\times7 = 105 \), actual \( y = 108 \) (close). For \( x = 4 \), \( y = 15\times4 = 60 \), actual \( y = 62 \) (close).

Step2: Test the second option \( y = 0.07x \)

For \( x = 8 \), \( y = 0.07\times8 = 0.56 \), which is way off from 120. So this is incorrect.

Step3: Test the third option \( y = 0.1x - 0.4 \)

For \( x = 8 \), \( y = 0.1\times8 - 0.4 = 0.4 \), way off from 120. Incorrect.

Step4: Test the fourth option \( y = 14.1x + 5.8 \)

For \( x = 8 \), \( y = 14.1\times8 + 5.8 = 112.8 + 5.8 = 118.6 \), not 120. For \( x = 9.5 \), \( y = 14.1\times9.5 + 5.8 = 133.95 + 5.8 = 139.75 \), not 138. Less accurate than the first option.

Comparing all, \( y = 15x \) gives the closest values to the actual data points overall.

Answer:

\( y = 15x \)