QUESTION IMAGE
Question
the table shows the educational attainment of a population, expressed in millions. find the odds in favor and the odds against a randomly selected member of the population with four years (or more) of college.
| less than 4 years high school | 4 years high school only | some college (less than 4 years) | 4 years college (or more) | total | |
|---|---|---|---|---|---|
| female | 13 | 32 | 19 | 19 | 83 |
| total | 29 | 61 | 38 | 35 | 163 |
the odds, in most reduced form, in favor of selecting a member of the population with four years (or more) of college are (square:square) (simplify your answers.)
the odds, in most reduced form, against of selecting a member of the population with four years (or more) of college are (square:square) (simplify your answers.)
Step1: Find number of people with 4+ years of college
The number of people with 4 years (or more) of college is the total in the "4 Years College (or More)" column, which is 35 million.
Step2: Find number of people without 4+ years of college
The number of people without 4 years (or more) of college is the total population minus the number of people with 4 years (or more) of college. So, $163 - 35=128$ million.
Step3: Calculate odds in - favor
The odds in favor of an event is the ratio of the number of favorable outcomes to the number of unfavorable outcomes. The odds in favor of selecting a member with 4 years (or more) of college is $\frac{35}{128}$.
Step4: Calculate odds against
The odds against an event is the ratio of the number of unfavorable outcomes to the number of favorable outcomes. The odds against selecting a member with 4 years (or more) of college is $\frac{128}{35}$.
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The odds in favor are $\frac{35}{128}$
The odds against are $\frac{128}{35}$