Question

test information description instructions from the list of choices, select the one best answer. multiple attempts not allowed. this test can only be taken once. force completion this test can be saved and resumed later. your answers are saved automatically. question completion status question 11 of 25 moving to another question will save this response. 4 points save answer question 11 a quarterback throws a pass at an angle of 35° above the horizontal with an initial speed of 25 m/s. the ball is caught by the receiver 2.55 seconds later. determine the horizontal distance the ball was thrown. 36 m 13 m 18 m 52 m 72 m

Explanation:

Step1: Find horizontal - velocity component

The initial speed is $v_0 = 25$ m/s and the launch - angle $\theta=35^{\circ}$. The horizontal component of the initial velocity is given by $v_{0x}=v_0\cos\theta$. So, $v_{0x}=25\cos35^{\circ}\approx25\times0.819 = 20.475$ m/s.

Step2: Calculate horizontal distance

The horizontal motion of the ball is a uniform - motion with constant velocity. The formula for the horizontal distance $x$ is $x = v_{0x}t$, where $t = 2.55$ s. Substitute $v_{0x}$ and $t$ into the formula: $x=20.475\times2.55\approx52$ m.

Answer:

D. 52 m