Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

test information description instructions multiple attempts this test a…

Question

test information
description
instructions
multiple attempts this test allows multiple attempts.
force completion this test can be saved and resumed later.
your answers are saved automatically.

question completion status:

moving to another question will save this response.

question 9

let ( y = f(x) ) be a quadratic function given by ( f(x) = ax^2 + bx + c ).

this function can have exactly one y-intercept.

○ true
○ false

moving to another question will save this response.

Explanation:

Step1: Recall y - intercept definition

The y - intercept of a function \(y = f(x)\) is found by setting \(x = 0\) and solving for \(y\). For the quadratic function \(f(x)=ax^{2}+bx + c\), when \(x = 0\), we have \(f(0)=a(0)^{2}+b(0)+c=c\).

Step2: Analyze the result

The value of \(f(0)\) is \(c\), which is a single value (since \(a\), \(b\), and \(c\) are constants for a given quadratic function). So, regardless of the values of \(a\) and \(b\) (as long as \(a
eq0\) for it to be quadratic), when \(x = 0\), there is exactly one value of \(y\) (which is \(c\)). So the function \(y = f(x)=ax^{2}+bx + c\) has exactly one y - intercept.

Answer:

True