Question

theo started to solve the quadratic equation ((x + 2)^2 - 9 = -5). he added 9 to both sides and the resulting equation was ((x + 2)^2 = 4). next, he took the square root of each side. which was the resulting equation of that step?
\\(\bigcirc\\) (x + 2 = \pm 4)
\\(\bigcirc\\) (x + 2 = \pm 2)
\\(\bigcirc\\) (x + 2 = \pm 8)
\\(\bigcirc\\) (x + 2 = \pm 16)

Explanation:

Step1: Identify current equation

The equation before square root is \((x + 2)^2 = 4\).

Step2: Take square root of both sides

Taking square root of both sides gives \(x + 2 = \pm \sqrt{4}\).

Step3: Simplify the square root

Since \(\sqrt{4} = 2\), the equation becomes \(x + 2 = \pm 2\).

Answer:

B. \(x + 2 = \pm 2\)