Question

there are 8.8 liters of gas in a piston at a pressure of 1.75 atmospheres. the temperature remains constant, and the gas is compressed to a volume of 6.2 liters. what is the new pressure, in atmospheres, inside the piston? enter your answer as a number, rounded to the nearest hundredth, with the appropriate unit, like this: 42.53 atm.

Explanation:

Step1: Identify Boyle's Law

Boyle's law is $P_1V_1 = P_2V_2$ for constant - temperature gas.

Step2: Assign values

$P_1 = 1.75$ atm, $V_1=8.8$ L, $V_2 = 6.2$ L. We need to find $P_2$.

Step3: Rearrange the formula

$P_2=\frac{P_1V_1}{V_2}$.

Step4: Substitute values

$P_2=\frac{1.75\times8.8}{6.2}=\frac{15.4}{6.2}\approx2.48$ atm.

Answer:

$2.48$ atm